Optimal. Leaf size=156 \[ \frac{8 a^2 (A+C) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}-\frac{4 a^2 (A-C) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d}-\frac{2 a^2 (5 A-C) \sin (c+d x) \sqrt{\cos (c+d x)}}{3 d}+\frac{8 A \sin (c+d x) \left (a^2 \cos (c+d x)+a^2\right )}{3 d \sqrt{\cos (c+d x)}}+\frac{2 A \sin (c+d x) (a \cos (c+d x)+a)^2}{3 d \cos ^{\frac{3}{2}}(c+d x)} \]
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Rubi [A] time = 0.424525, antiderivative size = 156, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3044, 2975, 2968, 3023, 2748, 2641, 2639} \[ \frac{8 a^2 (A+C) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}-\frac{4 a^2 (A-C) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d}-\frac{2 a^2 (5 A-C) \sin (c+d x) \sqrt{\cos (c+d x)}}{3 d}+\frac{8 A \sin (c+d x) \left (a^2 \cos (c+d x)+a^2\right )}{3 d \sqrt{\cos (c+d x)}}+\frac{2 A \sin (c+d x) (a \cos (c+d x)+a)^2}{3 d \cos ^{\frac{3}{2}}(c+d x)} \]
Antiderivative was successfully verified.
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Rule 3044
Rule 2975
Rule 2968
Rule 3023
Rule 2748
Rule 2641
Rule 2639
Rubi steps
\begin{align*} \int \frac{(a+a \cos (c+d x))^2 \left (A+C \cos ^2(c+d x)\right )}{\cos ^{\frac{5}{2}}(c+d x)} \, dx &=\frac{2 A (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \int \frac{(a+a \cos (c+d x))^2 \left (2 a A-\frac{3}{2} a (A-C) \cos (c+d x)\right )}{\cos ^{\frac{3}{2}}(c+d x)} \, dx}{3 a}\\ &=\frac{2 A (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{3 d \sqrt{\cos (c+d x)}}+\frac{4 \int \frac{(a+a \cos (c+d x)) \left (\frac{3}{4} a^2 (3 A+C)-\frac{3}{4} a^2 (5 A-C) \cos (c+d x)\right )}{\sqrt{\cos (c+d x)}} \, dx}{3 a}\\ &=\frac{2 A (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{3 d \sqrt{\cos (c+d x)}}+\frac{4 \int \frac{\frac{3}{4} a^3 (3 A+C)+\left (-\frac{3}{4} a^3 (5 A-C)+\frac{3}{4} a^3 (3 A+C)\right ) \cos (c+d x)-\frac{3}{4} a^3 (5 A-C) \cos ^2(c+d x)}{\sqrt{\cos (c+d x)}} \, dx}{3 a}\\ &=-\frac{2 a^2 (5 A-C) \sqrt{\cos (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{3 d \sqrt{\cos (c+d x)}}+\frac{8 \int \frac{\frac{3}{2} a^3 (A+C)-\frac{9}{4} a^3 (A-C) \cos (c+d x)}{\sqrt{\cos (c+d x)}} \, dx}{9 a}\\ &=-\frac{2 a^2 (5 A-C) \sqrt{\cos (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{3 d \sqrt{\cos (c+d x)}}-\left (2 a^2 (A-C)\right ) \int \sqrt{\cos (c+d x)} \, dx+\frac{1}{3} \left (4 a^2 (A+C)\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=-\frac{4 a^2 (A-C) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d}+\frac{8 a^2 (A+C) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}-\frac{2 a^2 (5 A-C) \sqrt{\cos (c+d x)} \sin (c+d x)}{3 d}+\frac{2 A (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{8 A \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{3 d \sqrt{\cos (c+d x)}}\\ \end{align*}
Mathematica [C] time = 6.43974, size = 865, normalized size = 5.54 \[ \sqrt{\cos (c+d x)} (\cos (c+d x) a+a)^2 \left (\frac{A \sec (c) \sin (d x) \sec ^2(c+d x)}{6 d}+\frac{\sec (c) (A \sin (c)+6 A \sin (d x)) \sec (c+d x)}{6 d}-\frac{(-2 A+C+C \cos (2 c)) \csc (c) \sec (c)}{2 d}+\frac{C \cos (d x) \sin (c)}{6 d}+\frac{C \cos (c) \sin (d x)}{6 d}\right ) \sec ^4\left (\frac{c}{2}+\frac{d x}{2}\right )+\frac{A (\cos (c+d x) a+a)^2 \csc (c) \left (\frac{\, _2F_1\left (-\frac{1}{2},-\frac{1}{4};\frac{3}{4};\cos ^2\left (d x+\tan ^{-1}(\tan (c))\right )\right ) \sin \left (d x+\tan ^{-1}(\tan (c))\right ) \tan (c)}{\sqrt{1-\cos \left (d x+\tan ^{-1}(\tan (c))\right )} \sqrt{\cos \left (d x+\tan ^{-1}(\tan (c))\right )+1} \sqrt{\cos (c) \cos \left (d x+\tan ^{-1}(\tan (c))\right ) \sqrt{\tan ^2(c)+1}} \sqrt{\tan ^2(c)+1}}-\frac{\frac{2 \cos \left (d x+\tan ^{-1}(\tan (c))\right ) \sqrt{\tan ^2(c)+1} \cos ^2(c)}{\cos ^2(c)+\sin ^2(c)}+\frac{\sin \left (d x+\tan ^{-1}(\tan (c))\right ) \tan (c)}{\sqrt{\tan ^2(c)+1}}}{\sqrt{\cos (c) \cos \left (d x+\tan ^{-1}(\tan (c))\right ) \sqrt{\tan ^2(c)+1}}}\right ) \sec ^4\left (\frac{c}{2}+\frac{d x}{2}\right )}{2 d}-\frac{C (\cos (c+d x) a+a)^2 \csc (c) \left (\frac{\, _2F_1\left (-\frac{1}{2},-\frac{1}{4};\frac{3}{4};\cos ^2\left (d x+\tan ^{-1}(\tan (c))\right )\right ) \sin \left (d x+\tan ^{-1}(\tan (c))\right ) \tan (c)}{\sqrt{1-\cos \left (d x+\tan ^{-1}(\tan (c))\right )} \sqrt{\cos \left (d x+\tan ^{-1}(\tan (c))\right )+1} \sqrt{\cos (c) \cos \left (d x+\tan ^{-1}(\tan (c))\right ) \sqrt{\tan ^2(c)+1}} \sqrt{\tan ^2(c)+1}}-\frac{\frac{2 \cos \left (d x+\tan ^{-1}(\tan (c))\right ) \sqrt{\tan ^2(c)+1} \cos ^2(c)}{\cos ^2(c)+\sin ^2(c)}+\frac{\sin \left (d x+\tan ^{-1}(\tan (c))\right ) \tan (c)}{\sqrt{\tan ^2(c)+1}}}{\sqrt{\cos (c) \cos \left (d x+\tan ^{-1}(\tan (c))\right ) \sqrt{\tan ^2(c)+1}}}\right ) \sec ^4\left (\frac{c}{2}+\frac{d x}{2}\right )}{2 d}-\frac{2 A (\cos (c+d x) a+a)^2 \csc (c) \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{5}{4};\sin ^2\left (d x-\tan ^{-1}(\cot (c))\right )\right ) \sec \left (d x-\tan ^{-1}(\cot (c))\right ) \sqrt{1-\sin \left (d x-\tan ^{-1}(\cot (c))\right )} \sqrt{-\sqrt{\cot ^2(c)+1} \sin (c) \sin \left (d x-\tan ^{-1}(\cot (c))\right )} \sqrt{\sin \left (d x-\tan ^{-1}(\cot (c))\right )+1} \sec ^4\left (\frac{c}{2}+\frac{d x}{2}\right )}{3 d \sqrt{\cot ^2(c)+1}}-\frac{2 C (\cos (c+d x) a+a)^2 \csc (c) \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{5}{4};\sin ^2\left (d x-\tan ^{-1}(\cot (c))\right )\right ) \sec \left (d x-\tan ^{-1}(\cot (c))\right ) \sqrt{1-\sin \left (d x-\tan ^{-1}(\cot (c))\right )} \sqrt{-\sqrt{\cot ^2(c)+1} \sin (c) \sin \left (d x-\tan ^{-1}(\cot (c))\right )} \sqrt{\sin \left (d x-\tan ^{-1}(\cot (c))\right )+1} \sec ^4\left (\frac{c}{2}+\frac{d x}{2}\right )}{3 d \sqrt{\cot ^2(c)+1}} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.175, size = 651, normalized size = 4.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (a \cos \left (d x + c\right ) + a\right )}^{2}}{\cos \left (d x + c\right )^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{C a^{2} \cos \left (d x + c\right )^{4} + 2 \, C a^{2} \cos \left (d x + c\right )^{3} +{\left (A + C\right )} a^{2} \cos \left (d x + c\right )^{2} + 2 \, A a^{2} \cos \left (d x + c\right ) + A a^{2}}{\cos \left (d x + c\right )^{\frac{5}{2}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (a \cos \left (d x + c\right ) + a\right )}^{2}}{\cos \left (d x + c\right )^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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